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The weight of 1 L sample of ozonised oxygen at STP was found to be 1.5 g When 100 " mL of " this mixture at STP was treated with turpentine oil, the volume was reduced to 90 mL. Calculate the molecular weight of ozone.

Answer» Volume absorbed by turpentive oil`=10mL`
`=` volume of `O_(3)`
Volume of `O_(2)=100-10=90mL`
Mw of ozonised oxygen`=(WeightxxRT)/(PV)`
`=(1.5xx0.0821xxRT)/(1xx1)=33.62`
Volume of mol ratio of `O_(2)` and `O_(3)` `=900:100`
Mw of ozonised oxygen`=(900xx32+100xxa)/(1000)`
`33.62=(900xx32+100xxa)/(1000)`
or `a=48.2`
Mw of `O_(3)=48.2`


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