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The weight of 1 L sample of ozonised oxygen at STP was found to be 1.5 g When 100 " mL of " this mixture at STP was treated with turpentine oil, the volume was reduced to 90 mL. Calculate the molecular weight of ozone. |
Answer» Volume absorbed by turpentive oil`=10mL` `=` volume of `O_(3)` Volume of `O_(2)=100-10=90mL` Mw of ozonised oxygen`=(WeightxxRT)/(PV)` `=(1.5xx0.0821xxRT)/(1xx1)=33.62` Volume of mol ratio of `O_(2)` and `O_(3)` `=900:100` Mw of ozonised oxygen`=(900xx32+100xxa)/(1000)` `33.62=(900xx32+100xxa)/(1000)` or `a=48.2` Mw of `O_(3)=48.2` |
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