1.

The weight of a man in a lift moving upwards is 608 N while the weight of the same man in the lift moving downwards, with the same acceleration is 368 N. His normal weight in Newton is

Answer»

488
588
480
240

Solution :Normal weight = MG
When lifts moving UPWARDS
w (G+ a) = 608...(1)
When lifts moving downwards
m (g-a) = 368...(2)
From EQUATIONS (1) and (2), `(m(g + a))/( m(g-a)) =608/368`
` (g+a)/(g-a)=38/23`
`implies 23g +23a = 38g-38a`
`implies I5g = 61A`
`therefore a =(15g)/61=(15xx10)/61=2.4ms^(-2)`
From equation (1)
m (g + a) = 608
`implies` m (10+ 2.4) = 608
`implies` m (12.4) = 608
`m=608/12.4=49.03`
Normal weight, `mg = 49.03 xx 10 = 490.3 kg`.


Discussion

No Comment Found

Related InterviewSolutions