1.

The weight of nickel (at.mass = 58.78) liberated by a current of 5 ampere flowing for 193 second through NiSO_(4) solution is

Answer»

`0.587` g
`5.87 `g
`0.2935` g
`2.935` g

SOLUTION :A/C to FARADAY's `1^(st)` law
`W_(Ni) = (58.7 xx 5 xx 193)/(2 xx 96500) = 0.2935` g


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