The weight of sodium carbonate required to prepare 500 ml of a semi-no – InterviewSolution

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1.	The weight of sodium carbonate required to prepare 500 ml of a semi-normal solution is
Answer» 13.25 g 26.5 g 53 g 6.125 g Solution :`N=(W xx1000)/(eq.wt. xx " volume in ml.")eq.wt.=(106)/(2)=53` `w=(0.5xx53xx500)/(1000)=13.25`.

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