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The wheel of a motor, accelerated uniformly from rest, rotates through 2.5 radian during the first second. Find the angle rotated during the next second. |
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Answer» As the angular acceleration is constant, we have `theta=omega_0t+1/2alphat^2=1/2alphat^2`. `Thus `2.5rad=1/2alpha(1s)^2` `alpha=5rad/s^2` or `alpha=5rad/s^2` the angle rotated during the first two seconds is `=1/2xx(5rad/s^2)(2s)62=10rad`. Thus the angle rotated during the 2nd second is `10rad-2.5rad=7.5rad.` |
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