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The wheel of a motor rotates with a constant acceleration of `4" rad s"^(-1)`. If the wheel starts form rest, how many revolutions will it make in the first 20 second? |
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Answer» The angular displacement in the first 20 s is given by `theta=omega_(0)t+(1)/(2)alphat^(2)=(1)/(2)("4 rads"^(-2)(20s)^(2))` `(because "Angular velocity" omega=0)` = 800 rad As, the wheel turns by `2pi` radian in each revolution, the number of revolutions in 20 s is `N=(theta)/(2pi)=(800)/(2pi)=128` |
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