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The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. The upper class limit of the highest class isA. 15B. 25C. 35D. 40 |
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Answer» Correct Answer - C Let x and y be the upper and lower class limit of frequency distribution. Given, width of the class =5 `rArr x-y=5` ……….(i) Also, given lower class (y)=10 On putting y=10 in Eq. (i), we get `x-10=5 rArr x=15` So, the upper class limit of the lowest class is 15. Hence, the upper limit of the highest class = (Number of continuous classes x Class with + Lower class limit of the lowest class) `=5 xx 5 + 10 = 25+10=35` Hence, the upper class limit of the highest class is 35. Alternate method After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15, 15-20, 20-25, 25-30, and 30-35. Thus, the highest class is 30-35, Hence, the upper limit of the class is 35. |
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