1.

The width of the diffraction band varies

Answer»

inversely as the wavelength
DIRECTLY as the width of the slit
directly as the distance between the slit and the SCREEN
inversely as the size of the SOURCE from which the slit is illuminated.

Solution :Width of the DIFFRACTION band, `beta = (D lambda)/(a)` where D = distance between slit and the screen, a = width of the slit `lambda =` wavelength.


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