1.

the work done against force of friction isA. 8.7 JB. 10.7 JC. 7.8 JD. 12.7 J

Answer» Correct Answer - A
Work against friction is `W_f=fd=muNd=mumgcosthetad " " (therefore N=mgcos theta)`
`=0.1xx1 kg xx 10 m s^(-2) xx cos 30^@ xx 10 m`
=8.7 J


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