

InterviewSolution
Saved Bookmarks
1. |
the work done against force of friction isA. 8.7 JB. 10.7 JC. 7.8 JD. 12.7 J |
Answer» Correct Answer - A Work against friction is `W_f=fd=muNd=mumgcosthetad " " (therefore N=mgcos theta)` `=0.1xx1 kg xx 10 m s^(-2) xx cos 30^@ xx 10 m` =8.7 J |
|