InterviewSolution
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InterviewSolution
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The work done by the external ajent in stretching a spring of force constant `k` from length `l_(1)`to `l_(2)` isA. `k(l_(2)^(2) - l_(1)^(2))`B. `(1)/(2)k(l_(2)^(2) - l_(1)^(2))`C. `k(l_(2) - l_(1))`D. `k//2(l_(2) - l_(1))` |
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Answer» Correct Answer - B `U_(2) = (1)/(2)Kl_(2)^(2)` ` U_(1) = (1)/(2)Kl_(2)^(2)` `W=U_(2) - U_(1)` `(1)/(2)Kl_(2)^(2)- (1)/(2)Kl_(1)^(2) = (1)/(2)K(l_(2)^(2)- l_(1)^(2))` |
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