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The work done by the system in a cyclic process involving one mole of an ideal monoatomic gas is `-50 kJ//cycle`. The heat absorbed by the system per cycle isA. ZeroB. `50 kJ`C. `-50 kJ`D. `250 kJ` |
Answer» Correct Answer - B For a cyclic process, the work done is equal to heat absorbed `q=DeltaE-W` `:. DeltaE=0` Thus, `q=-W=50 kJ` |
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