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The work done by the system in the conversion of `1 mol` of water at `100 ^(@)C` and `760` torr to steam is `-3.1 kJ`. Calculate the `DeltaE` for the conversion (Latent heat of vaporisation of water is `40.65 kJ mol^(-1)`)A. `43.75 kJ`B. `101.35 kJ`C. `37.55 kJ`D. `-40.65 kJ` |
Answer» Correct Answer - C According to first law, `DeltaE=q+W` `:. DeltaE=40.65-3.1=37.55 kJ` |
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