1.

The work done by the system is 8 joule, when 40 joule heat is supplied to it. What is the increases in internal energy of system.

Answer»

25 J
30 J
32 J
28 J

Solution :`q=40 J`
`w=8 J` (WORK DONE by the SYSTEM)
`DeltaE=q+w=40-8=32 J`


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