InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The work done during the expanision of a gas from a volume of `4 dm^(3)` to `6 dm^(3)` against a constant external pressure of 3 atm is (1 L atm = 101.32 J)A. `- 6 J`B. `- 608 J`C. `+ 304 J`D. `- 304 J` |
|
Answer» Correct Answer - B Work done by the system during an irreversible expansion againt a constant atmospheric pressure is given by `W = - P_(ext) Deltav = - P_(ext) (V_(f) - V_(i))` `= - 3 atm (6 L - 4 L)` `= - 6 L atm` ` = - L atm ((101.32 J)/(1 L atm))` `= - 607.92 kJ` |
|