1.

The work done during the expansion of a gas from a volume of `4dm^(3)` to `6dm^(3)` againts a constant external presuure of `3atm` is `(1atm-L=101.32J)`A. `-6J`B. `-608J`C. `+304J`D. `-304J`

Answer» Correct Answer - B
Work done `(W)=-P_(ext.)(V_(2))-V_(1))`
`=-3xx6(6-4)=-6L-atm`
`=-6xx101.32J ( :. 1L atm =101.32J)`
`=-607.92~~608J.`


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