The work function for metals A,B and C are respectively 1.92 eV, 2.0 eV and 5.0 eV. According to Einstein's equation, the metals which will emit photoelectrons for a radiation of wavelength 4100 Å is/are

The work function for metals A,B and C are respectively 1.92 eV, 2.0 e

1.	The work function for metals A,B and C are respectively 1.92 eV, 2.0 eV and 5.0 eV. According to Einstein's equation, the metals which will emit photoelectrons for a radiation of wavelength 4100 Å is/are
Answer» NONE of these a only A and B only all the three metals. Solution :Energy of photon of radiation `4100Å=4.1xx10^(-7)m` in eV will be `E=(hc)/(elamda)=(6.63xx10^(-34)xx3xx10^(8))/(1.6xx10^(-19)xx4.1xx10^(-7))=3.03eV` As work functions for metals A and B are 1.92 eV and 2.00 eV RESPECTIVELY and are less than the energy of incident photon, hence metals A and B will EMIT photoelectrons.

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The work function for metals A,B and C are respectively 1.92 eV, 2.0 eV and 5.0 eV. According to Einstein's equation, the metals which will emit photoelectrons for a radiation of wavelength 4100 Å is/are

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