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The work function for tungsten and sodium are `4.5 eV` and `2.3 eV` respectively . If the threshold wavelength `lambda` for sodium is `5460 Å`, the value of `lambda` for tungsten isA. `5893 Å`B. `10683 Å`C. `2791 Å`D. `528 Å` |
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Answer» Correct Answer - C Since `W_(0) = (hc )/(lambda_(0)), :. ((W_(0))_ T)/((W_(0))_(Na)) = (lambda_(Na))/(lambda_(T))` or `lambda_(T) = ((lambda_(Na)) xx (W_(0))_(Na))/((W_(0))T) = ( 5460 xx 2.3)/(4.5) = 2791 Å` |
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