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The work function of a metal surface is 4.2 eV. The maximum wavelength which can eject photo-electron from this surface is =…….Å |
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Answer» 2956 `THEREFORE lambda_(0)=(hc)/(phi_(0))=(6.6xx10^(-34)xx3xx10^(8))/(4.2xx1.6xx10^(-19))` `therefore lambda_(0)=2956xx10^(-10)m` `therefore lambda_(0)2956Å` |
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