1.

The work function of a metal surface is 4.2 eV. The maximum wavelength which can eject photo-electron from this surface is =…….Å

Answer»

2956
3076
4116
5088

Solution :`phi_(0)=hf_(0)=(HC)/(lambda_(0))`
`THEREFORE lambda_(0)=(hc)/(phi_(0))=(6.6xx10^(-34)xx3xx10^(8))/(4.2xx1.6xx10^(-19))`
`therefore lambda_(0)=2956xx10^(-10)m`
`therefore lambda_(0)2956Å`


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