1.

The work function of a metallic surface in 5.0/eV. Photoelectrons are emitted when light of lamda=2000Å falls-on it. The P.D. to stop fastest photoelectrons is :

Answer»

1.2 V
2.4 V
3.6 V
4.8 V.

Solution :`V=(hv-w)/(E)=(hc//lambda-w)/(e)`
`-1.2 V` on SOLVING


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