1.

The work function of a metallic surface is 5.01 e V. The photoelectrons emitted when light of wavelength 2000 A^@ falls on it . The potential difference applied to stop the fastest photo electrons is : (h = 4.14 xx 10^(-15) e V)

Answer»

2.24 V
1.2 V
4.8 V
3.6 V

Answer :B


Discussion

No Comment Found

Related InterviewSolutions