Saved Bookmarks
| 1. |
The work function of a photosensitive element is 2eV. Calculate the velocity of a photoelectron when the element is exposed to a light of wavelength 4xx10^(3) A. |
|
Answer» Solution :Einstein.s photoelectric equation is `(1)/(2)mv^(2)=(HC)/(lamda)-W_(0)` `(1)/(2)mv^(2)=(6.62xx3)/(4xx10^(3)xx10^(-10))xx10^(-26)-2xx1.6xx10^(-19)` `v^(2)=(1.765xx2)/(9.1)xx10^(12)` `v=sqrt((1.765xx2)/(9.1))xx10^(6)=6.228xx10^(5)ms^(-1)` |
|