

InterviewSolution
Saved Bookmarks
1. |
The work function of a surface of a photosensitive material is `6.2 eV`. The wavelength of the incident radiation for which the stopping potential is `5 V` lies in theA. Infrared regionB. X-ray regionC. Ultraviolet regiD. Visible region |
Answer» Correct Answer - C `E_("incident")=W+K_("max"),K_("max")=eV_(0)` `hv=hv_(0)+eV_(0)," stopping potential "=V_(0)` `(hc)/(lambda)=6.2e+5e` `lambda=(hxxc)/(11.2xx1.6xx10^(-19))=(6.63xx10^(-34)xx3xx10^(8))/(11.2xx1.6xx10^(-19))` `=1.1xx10^(-7)m` |
|