1.

The work function of photometal is 6.626 eV. What is the threshold wavelength ?

Answer»

3921 `Å`
1875 `Å`
1867 `Å`
4433 `Å`

Solution :`lambda_(0) = (HC)/(W_(0)) = (6.63 XX 10^(-34) xx 3 xx 10^(8) xx 10^(10))/(6.626 xx 1.6 xx 10^(-19)) Å = 1875 Å`


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