The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7^(@)C. The gas is (R 8 cdot 3J" mol"^(-1) K^(-1)):

The work of 146 kJ is performed in order to compress one kilo mole of

1.	The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7^(@)C. The gas is (R 8 cdot 3J" mol"^(-1) K^(-1)):
Answer» DIATOMIC triatomic a mixture of MONOATOMIC and diatomic monoatomic Solution :WORK done during adiabatic process `W=nC_(v)Delta T` `146xx10^(3)=10^(3)C_(v)xx7 rArr C_(v)=20 cdot 85 J" mol"^(-1)K^(-1)` This is same as `C_(v)` for diatomic gas `C_(v)=(5)/(2) R` Thus, CORRECT choice is (a).

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The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7^(@)C. The gas is (R 8 cdot 3J" mol"^(-1) K^(-1)):

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