1.

The wt. in g of 1 curie of radioactive element ""^(200)X having a t_(1//2) of 63.3 is

Answer»

`3.7 xx 10^(-8)` G
`200 g`
`7.4 xx 10^(-8) g`
`3.0 xx 10^(-8) g`

Solution :`lambda = (0.693)/(t_(1//2)) = (0.693)/(69.3) "MIN"^(-1) = 10^(-2) "min"^(-1)`
1 Curie = `3.7 xx 10^(10) DS^(-1) = 3.7 xx 10^(10) xx 60 d "min"^(-1)`
`= 2.22 xx 10^(12) d "min"^(-1) = lambda N = 10^(-2) N`
or `N = 2.22 xx 10^(14)` atoms.
`=(200)/(6.023 xx 10^(23)) xx 2.22 xx 10^(14) = 7.4 xx 10^(-8) g`.


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