1.

The wt. of unhydrous sodium carbonate needed to prepare 500 ml of a decinormal solution would be

Answer»

5.3 g
10.6g
1.06 g
2.65 g

Solution :WT. PER `DM^(3) = N xx EQ. Wt.`
`= 0.1 xx 53 = 5.3 g`
Wt. in 500 ml `= (5.3)/2= 2.65 g.


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