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The x and y coordinates of the particle at any time are `x=5t-2t^(2) and y=10t` respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:A. ` 5 m//s^(2)`B. ` -4 m//s^(2)`C. ` -8 m//s^(2)`D. 0 |
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Answer» `x = 5t - 2t^(2)` `v_(x) = (dx)/(dt) = 5 - 4 t` `a_(x) = (dv_(x))/(dt) = - 4` `y = 10 t` `v_(y) = (4s)/(dt) = 10` `a_(y) = (dv_(y))/(dt) = 0` `a = a_(x) = - 4 m//s^(2)` |
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