InterviewSolution
`4f ^(14) 5D^(1) 6s^(0)``4f^(14) 5d^(0) 6s^(0) and 4f^(14) 5d^(1)6s^(0)` respectively `4f^(14) 5d^(0)6s^(0)``4f^(14) 5d^(1) 6s^(2)`
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