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The yeild of a nuclear reaction producing radionuclides may be described in two ways: either by the ratio omega of the numbers of nuclear reactions to the number of bombarding particles, or by the quantity k, the ratio of the activity of the formed radionuclide to the number of bombarding particles, Find: (a) the half-life of the formed radionuclide, assuming omega and k to be known: (b) the yield omega of the reaction Li^(7)(p,n)Be^(7) if after irradiation of a lithum target by a beam or protons(over t=2.0) hours and with =1.35.10^(8)dis//s and its half-life to T=53 days. |
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Answer» Solution :(a) Assuming of COURSE, that each reaction produces a radio nuclide of the same type, the decay constant `alpha` of the radionuclide is `k//W`. Hence `T=(In 2)/(LAMBDA)=(w)/(l)In2` (b) number of bombarding particles is : `(It)/(E )` (e = charge on proton.) Then the number of `Be^(7)` produced is : `(It)/( e)w`. If `lambda=` decay constant of `Be^(7)=(In2)/(T)`, then the acitvity is `A=(It)/(e )omega. (In2)/(T)` Hence `w=(eAT)/(It In 2)= 1.98xx10^(-3)` |
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