1.

Theequivalent resistance of two resistors connected in series is 6 Omega and their parallel equivalent resistance is 4/3 Omega. What are the values of resistances ?

Answer»

`4Omega, 6 Omega`
`8 Omega, 1 Omega`
`4 Omega, 2 Omega`
`6 Omega, 2 Omega`

Solution :`R_(1) + R_(2) = 6`
`(R_(1)R_(2))/(R_(1) = R_(2)) = (4)/(3) RARR R_(1)R_(2) = 8 Omega rArr R_(1) = 2Omega, R_(2) = 4 Omega`


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