1.

Thenormality of 10% (weight/volume) acetic acid is

Answer»

1 N
10 N
1.66 N
0.83 N

Solution :Normality `= (w)/(E.V) = (10G)/(100 mL)xx(1)/(60)`
`= (10g)/((100)/(1000)xx60) = 1.66 N`


Discussion

No Comment Found

Related InterviewSolutions