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There are 10 capacitors. each of capacitance 10 muF. The ratio of maximum to minimum capacitance obtained by their combination is ......

Answer»

`5:1`
`10 :1`
`50 :1`
`100 :1`

Solution :Since in PARALLEL connection, maximum capacitance `C_(1)` is obtained.
`C_(1) = nC = 10xx10= 100 muF `
In series connection, minimum capacitance `C_(2)` is obtained.
`C_(2) = (C)/(n) = (10)/(10)= 1 mu F `
`:. (C_(1))/(C_(2))= (100)/(1) = 100 :1`


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