There are 3 red, 5 blue and 2 yellow balls in a box. Two balls are drawn at random without replacing the first one. Find the probability that i) at least one is yellowii) Both of them are not red

There are 3 red, 5 blue and 2 yellow balls in a box. Two balls are dra

1.	There are 3 red, 5 blue and 2 yellow balls in a box. Two balls are drawn at random without replacing the first one. Find the probability that i) at least one is yellowii) Both of them are not red
Answer» Balls in the box RED---3 BLUE-----5 YELLOW ----2 Total ---------10 i) Probability that 1st ball drawn is not yellow will be 8/10 Probability that 2nd ball drawn without replacement is not also yellow will be 7/10 As the events are idepedent ,then probability that both the balls drawn one after another is not yellow will be 8/10×7/9=28/45 Hence probability of drawing at least one yellow ball will be = 1-28/45=17/45. ii) Probability that 1st ball drawn is red will be =3/10 Probability that 2nd ball drawn without replacement of first red ball is also red will be 2/9 Then probability that both are not red wil be =1-3/10×2/9=1-1/15=14/15

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There are 3 red, 5 blue and 2 yellow balls in a box. Two balls are drawn at random without replacing the first one. Find the probability that i) at least one is yellowii) Both of them are not red

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