Saved Bookmarks
| 1. |
There are `4sqrt2xx10^6` radioactive nuclei in a given radioactive sample. If half life of sample is 20s, how many nuclei will decay in 10seconds? |
|
Answer» Here, `N_0=4sqrt2xx10^6`, `T=20s, t=10s`, form `N/(N_0)=(1/2)^(t//T)=(1/2)^(10//20)=(1/2)^(1//2)=1/(sqrt2)` `N=(N_0)/(sqrt2)=(4sqrt2)/(sqrt2)xx10^6=4xx10^6` Number of nuclie decayed=`N_0-N` `=4sqrt2xx10^6-4xx10^6` `=4xx10^6(sqrt2-1)` `=4xx0.414xx10^6=1.656xx10^6` |
|