InterviewSolution
Saved Bookmarks
| 1. |
There are 5 balls in a vessel. Out of which 2 are red, 2 are blue and ‘1’ is green. When a ball is selected at random, then probability that the ball is not a red ball ………………… A) 1/5 B) 2/5 C) 3/5 D) 4/5 |
|
Answer» Correct option is (C) 3/5 Red balls = n(R) = 2, Blue balls = n(B) = 2 and Green balls = n(G) = 1 N(S) = n(R) + n(B) + n(G) = 2+2+1 = 5 Number of balls which are not red is n(R') = 5 - n(R) = 5 - 2 = 3 \(\therefore\) Probability that the selected ball is not a red ball is P(R') \(=\frac{n(R')}{n(S)}=\frac35\) Correct option is C) 3/5 |
|