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There are `6.02 xx 10^(22)` molecules each of `N_(2),O_(2)` and `H_(2)` which are mixed together at `760 mm` and `273 K`. The mass of the mixture in grams is `:`A. `6.2`B. `4.12`C. `3.09`D. 7 |
Answer» Correct Answer - 1 Moles of each gas `=(6.02xx10^(22))/(N_(A))=0.1` So mass of mixture `=0.1xxM_(N_(2))+0.1xxM_(O_(2))+0.1xxM_(H_(2))` `=0.1xx28+0.1xx32+0.1xx2=6.2 ` grams. |
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