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There are 6 bag in each bag has 5 balls how many balls will one third of these bags have? |
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Answer» There are 5 black and 6 red balls in the bag.2 black balls can be selected out of 5 black BALL in 5C2 WAYS and 3 red ball can be selected out of 6 red balls in 6C3 ways.Thus, by multiplication principle, required NUMBER of ways of selecting 2 black and 3 red balls is 5C2×6C3=2!3!5!×3!3!6!=25×4×3×2×16×5×4=10×20=200 |
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