1.

There are n electrons of charge on a drop of oil of density rho. It is in equilibrium in an electric field E. Then radius of drop is

Answer»

`[(2n e E)/(4pi RHO G)]`
`[(N eE)/(rho g)]`
`[(3n e E)/(4pi rho g)]`
`[(2n e E)/(PI rho g)]`

Answer :C


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