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There are `n`letters and`n`addressed envelopes. Find the probability that all theletters are not kept in the right envelope. |
Answer» Correct Answer - `1 - (1)/(n!)` Required probability is 1 - P(all letters in right envelope) = 1 - 1/n! (As there are total number of n! ways in which letters can take envelopes and just one way in which they have corresponding envelopes.) |
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