There are only two women among 20 persons taking part in a pleasuretrip. The 20 persons are divided into two groups, each group consisting of 10person. Then the probability that the two women will be in the same group is`9//19`b. `9//38`c. `9//35`d. noneA. `9//19`B. `9//38`C. `9//35`D. none of these

There are only two women among 20 persons taking part in a pleasuretri

1.	There are only two women among 20 persons taking part in a pleasuretrip. The 20 persons are divided into two groups, each group consisting of 10person. Then the probability that the two women will be in the same group is`9//19`b. `9//38`c. `9//35`d. noneA. `9//19`B. `9//38`C. `9//35`D. none of these
Answer» Correct Answer - A The number of ways in which 20 people can be divided into two equal group is `n(S) = (20!)/(10! 10! 2!)` The number of ways in which 18 people can be divided into groups of 10 and 8 is `n(E) = (18!)/(10! 8!)` `therefore P(E) = (18!)/(10! 8!) (10! 10! 2)/(20!) = (10 xx 9 xx 2)/(20 xx 19) = (9)/(19)`

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