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There are three families A, B and C. Family A has 2 men, 4 women and 3 children. Family B has 3 men, 3 women and 2 children. Family C has 2 men, 2 women and 5 children. A man earns 500 per day and spends 300 per day. A woman earns * 400 per day and spends * 250 per day. A child spends *40 per day. Find the money each family saves per day using matrices. |
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Answer» Answer: family a => men = 500× 2 - 300 × 2 = 400 women = 400 × 4 - 250 × 4 = 600 children = - 60 × 3 = 120 TOTAL SAVING of family a = 600 + 400 - 120 = 880 RS family b => men = 500 × 3 - 300 × 3 = 600 rs women = 3 × 400 = 1200 - 250 × 3 = 550 rs children = 5 × - 40 = - 200 total saving = 600 + 550 - 200 = 950 rs family c = men = 2 × 500 = 1000 - 300 × 2 = 400rs women = 400 × 2 - 250 × 2 = 300 rs children = - 40 × 5 = - 200 total saving = 400 + 300 - 200 = 500 rs therefore, total savings of three families are -- FAMILY a = 880 rs FAMILY B = 950 rs FAMILY C = 500 rs very INTERESTING question PLEASE MARK AS BRAINLIEST MY DEAR BROTHER OR SISTER |
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