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There are two cylindrical pillars at the front of larger dome, If the radius of each pillar is 1m and height is 13m. Then find the total surface area (excluding its base and top) of each pillar. |
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Answer» Answer: Rs. 1351.68 Step-by-step EXPLANATION: \begin{gathered}\text{Radius of each pillar = 28 cm = 0.28 m}\\\\\text{Height of each pillar = 4 m}\\\\\text{CSA of 1 pillar = 2} \pi r h\\\\= 2 \times \dfrac{22}{7} \times 0.28 \times 4\\\\\\= \dfrac{49.28}{7}\\\\\\= 7.04 \: m^2\\\\\text{Area of 24 pillars = 7.04(24) = 168.96 cm}^2\\\\\text{COST of painting per m$^2$ = Rs. 8}\\\\\text{Total cost = Rs. 8} \times 168.96 = \textbf{Rs. 1351.68}\END{gathered} Radius of each pillar = 28 cm = 0.28 m Height of each pillar = 4 m CSA of 1 pillar = 2πrh =2× 7 22
×0.28×4 = 7 49.28
=7.04m 2
Area of 24 pillars = 7.04(24) = 168.96 cm 2
Cost of painting per m 2 = Rs. 8 Total cost = Rs. 8×168.96=Rs. 1351.68
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