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There is a black spot at the bottom of a rectangular glass slab of thickness d and refractive index mu. When the spotis viewed perpendicularly from above, the spot appears to be shifted through a distance (mu-1)/(mu) towards the observer. Prove it. |
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Answer» Solution :Read DEPTH of the black spot from the UPPER surface of the glass slab = d Let the apparent depth of the black spot from the upper surface of the glass slab be `d_(1)` REFRACTIVE index of glass `mu = (d)/(d_1) or, d_(1) = (d)/(mu)` `therefore` Apparent DISPLACEMENT of the black spot towards the observer `= d - d_(1) = d - (d)/(u) = d (1 - (1)/(mu)) = d ((mu-1)/(mu))` |
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