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There is a fixed positive charges Q at O, and A and B are points equidistant from O. A positive charge +q is taken slowly by an external agent from A to B along the line AC and then along the line CB. |
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Answer» The TOTAL work done on the charge is zero. (a) is correc because potential of `A` and `B` is same. (b) is correct because charge is going from LOW potential to high potential. Electric potential energy increases and electrostatic forces do negative work. Similarly (c) is ALSO correct.
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