There is a hollow cylinder of radius R and it is rotating with constant angular speed omega. There is a point mass which rotates along with the cylinder and geta carried upward. Friction is enough such that the point mass does not slip with respect to the cylinder as long as the normal force is becomes zero. If the path of the particle after it lost contact with the cylinder is as shown in the figure then, What is the value of omega (in terms of g and R)

There is a hollow cylinder of radius R and it is rotating with constan

1.	There is a hollow cylinder of radius R and it is rotating with constant angular speed omega. There is a point mass which rotates along with the cylinder and geta carried upward. Friction is enough such that the point mass does not slip with respect to the cylinder as long as the normal force is becomes zero. If the path of the particle after it lost contact with the cylinder is as shown in the figure then, What is the value of omega (in terms of g and R)
Answer» `sqrt(g/(sqrt(3)R))` `sqrt(g/(2sqrt(pi)R))` `sqrt(g/(2R))` `sqrt(g/(sqrt(2)R))` SOLUTION :`1/2gsintheta. (4v^(2))/(g^(2)COS^(2)theta)=2R`……..(1) `V^(2)=Rgsintheta`……(2) From (1) and (2) `tantheta=1`

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