there is a playground of dimensions 60 m * 45 m. in two corners of the

1.	there is a playground of dimensions 60 m * 45 m. in two corners of the ground two pits each of dimensions 4m * 3m * 2m are dug and the mud is spread all over the ground uniformly. Find the approximate height of the layer of mud spread
Answer» ANSWER:AREA of ground = 50×30=1500m^2. Volume of PIT dug =4×5×1=20 m^3. Area of pit=20m^2. 20m^3 of MUD is spread over an area of (1500m^2.-20m^2)=1480m^2. Volume =Area × HEIGHT Hence, 20m^3=1480 m^2×height Therefore, height = (20/1480)×1000 mm =13.5135mm Hope it helps. $itsbrainlybiswa$

there is a playground of dimensions 60 m * 45 m. in two corners of the ground two pits each of dimensions 4m * 3m * 2m are dug and the mud is spread all over the ground uniformly. Find the approximate height of the layer of mud spread

Answer»

ANSWER:AREA of ground = 50×30=1500m^2.

Volume of PIT dug =4×5×1=20 m^3.

Area of pit=20m^2.

20m^3 of MUD is spread over an area of (1500m^2.-20m^2)=1480m^2.

Volume =Area × HEIGHT

Hence,

20m^3=1480 m^2×height

Therefore, height = (20/1480)×1000 mm

=13.5135mm

Hope it helps.

$itsbrainlybiswa$