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There is a point object at a height h above the surface of water in a tank. If the bottom of the tank acts as a plane mirror where will be the image formed? If an observer looks from air at the surface of water normally, calculate the distance of the image from that surface of water of the tank formed by the mirror-like bottom surface of the tank. Refractive index of water =(4)/(3). |
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Answer» Solution :Q is a POINT source. For refraction in water the apparent position of Q is Q. [Fig. 2.57]. `"So", "" MU = ("apparent HEIGHT")/("real height") = (PQ.)/(PQ)` `= (PQ.)/(h)` `or, "" PO. = mu^(h) = (4)/(3)h` Therefore the distance of Q. from the bottom of the tank `= d + (4)/(3)h` So the image of Q. will be formed at a distance of `(d + (4)/(3)h)`from the bottom of the tank. The distance of the image from the surface of water ` = d + d(4)/(3)h = 2d + (4)/(3)h` If the apparent distance of the image from the surface of water the EYE of an observe in air medium is x then, `(4)/(3) = (2d + (4)/(3)h)/(x)` `or, "" x = (4)/(3) (2d + (4)/(3)h) = (3)/(2)d + h` 
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