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There is a sample containing 16g of radioactive material, the half-life of which is 2 days. What is the amount of sample left after 32 days: |
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Answer» Solution :`m/m_(0)=(1/2)^(t/T)` T=2 days and t=32 days `m/m_(0)=[1/2]^((32)/(2)) =[1/2]^(16)` `m=m_(0) [1/2]^(16)=16 xx 1/(2^(16))=(1)/(4096)g` `approx 0.24 mg LT 1 mg` |
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