InterviewSolution
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InterviewSolution
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There is a spherical glass shell of refractive index 1.5, inner radius 10 cm and outer radius 20 cm. Inside th espherical cavity, there is air. A point object is placed at a point O at a distance of 30cm from the outer spherical surface. Find the final position of th eimage as seen eye. |
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Answer» Correct Answer - `18.75` cm from centre. `(1.5)/(v)-(1)/(-30)=(1.5-1)/(20)rArrv=-180cm` For second surface, `u_(1)=-190cm` `rArr (1)/(v)-(1.5)/(-190)=(1-1.5)/(10)rArr v=(190)/(11)` For third surface, `u=-((190)/(11)+20)=(-410)/(11)` `rArr(1.5)/(v)-(11)/(410)=(1.5-1)/(-10)=-(1)/(20)` `rArr v=-(410)/(21)` For fourth surface , `u=-((410)/(21)+10)=-(620)/(21)cm` `mu_(1)=1.5, mu_(2)=1,R=-20cm` `rArr (1)/(v)+(1.5xx21)/(620)=(1-1.5)/(-20)` `rArr v=-38.75 cm` The final image is at a distance of `18.75cm` from the center. |
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