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There is a uniform magnetic field B normal to the xy plane. A conductor ABC has length AB=l_(1), parallel to the x-axis, and length BC=l_(2), parallel to the y-axis. ABC moves in the xy plane with velocity v_(x)hat(i)+v_(y)hat(j). The potential difference between A and C is proportional to |
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Answer» `v_(x)l_(1)+v_(y)l_(2)` `V_(A)-V_(C )=BV_(x)l_(2)-BV_(y)l_(1)` `V_(A)-V_(C )=B(V_(x)l_(2)-V_(y)l_(1))` |
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